- Get link
- X
- Other Apps
Question:
Two people are to meet in the park. Each
person is equally likely to arrive, independent of the other, at 2:00, 2:30, or
3:00 pm. Let X equal the time that the first person to arrive has to wait,
where X is taken to equal 0 if both people arrive at the same time.
(a)
What
are the possible values of X?
(b)
What
are the probabilities that X assumes each of these values?
Solution:
Person 1 arrival time
|
Person 2 arrival time
|
The time that the first person to arrive has to wait
|
2:00
|
2:00
|
0 mins
|
2:30
|
30 mins
|
|
3:00
|
60 mins
|
|
2:30
|
2:00
|
30 mins
|
2:30
|
0 mins
|
|
3:00
|
60 mins
|
|
3:00
|
2:00
|
60 mins
|
2:30
|
30 mins
|
|
3:00
|
0 mins
|
Answer (a):
The possible values that X can take are:
·
0 mins
·
30 mins
·
60 mins
Answer
(b):
Let X = the time that the first person to
arrive has to wait
Probability distribution of X is as below
X
|
Frequency
|
P(X)
|
0 mins
|
3
|
3/9
|
30 mins
|
4
|
4/9
|
60 mins
|
2
|
2/9
|
Total
|
9
|
9/9
|
Comments
Post a Comment